If a -b = 0.9 and ab = 0.36 ; find a 2 - b 2
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a - b = 0.9
a = 0.9 + b
ab = 0.36
(0.9+b) b = 0.36
0.9b + b^2 = 0.36
b^2 + 0.9b - 0.36 = 0
b^2 + 1.2b - 0.3b - 0.36 = 0
b(b+1.2) - 0.3(b + 1.2) = 0
(b+1.2)(b-0.3) = 0
b = -1.2 or 0.3
If b = 1.2 then a =
a - 1.2= 0.9
a = 0.9 + 1.2
a = 2.1
If b = 0.3 then a =
a - 0.3 = 0.9
a = 0.9 + 0.3
a = 1.2
a = 0.9 + b
ab = 0.36
(0.9+b) b = 0.36
0.9b + b^2 = 0.36
b^2 + 0.9b - 0.36 = 0
b^2 + 1.2b - 0.3b - 0.36 = 0
b(b+1.2) - 0.3(b + 1.2) = 0
(b+1.2)(b-0.3) = 0
b = -1.2 or 0.3
If b = 1.2 then a =
a - 1.2= 0.9
a = 0.9 + 1.2
a = 2.1
If b = 0.3 then a =
a - 0.3 = 0.9
a = 0.9 + 0.3
a = 1.2
Answered by
1
Answer:
±1.35
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