Question

if a+b=0 then (1+x^a)^-1+(1+x^b)^-1=​

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Answer:

1

Step-by-step explanation:

(1+x^a)^-1+(1+x^b)^-1

={1+x^a+1+x^b}÷{(1+x^a)(1+x^b)}

={2+x^a+x^b}÷{1+x^a+x^b+x^(a+b)}

={2+x^a+x^b}÷{1+x^a+x^b+x^0}. [as a+b =0]

={2+x^a+x^b}÷{1+x^a+x^b+1}. [ as x^0=1]

={2+x^a+x^b}÷{2+x^a+x^b}

=1