Math, asked by vivek829478, 7 months ago

if (a+b)=0 then a^2+b^2+16 is

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Answered by ravanji786

Answer:

Given, (a×b)2+(a⋅b)2=144

⇒(a2b2⋅1⋅sin2θ)+a2b2cos2θ=144

⇒a2b2(sin2θ+cos2θ)=144

⇒a2b2=144

⇒16b2=144(∵|a|=4)

⇒b2=9

⇒b=3

or |b|=3

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Answered by Anonymous

Answer:

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