Question

IF À B = 0, what is the angle between A and
4.
Solution:
and B.​

Answer 1

Answer:

0 degree, because, vector A×vector B=n^ AB sin theta, where, n^(read it as eta cap) is the unit vector perpendicular to the plane formed by vector A and vector B,i.e, perpendicular to both vector A and vector B, A is the magnitude of vector A and B is the magnitude of vector B and theta is the angle between vector A and vector B. Now, if theta=0, or, son theta=sin 0=0, only then vector A×vector B=0[assuming vector A and vector B are not null vectors]. But theta=0, means that vector A and vector B are collinear or parallel, so,the two vectors (A and B) are either collinear or parallel. (Answer)

Answer 2

Answer:

It is zero

the dot product are zero

a.b=abcos theta

cos theta =0

theta =90

thus angle between A and B is 90