Question

if a+b+1=0 then a^3+b^3+1-3ab​

Answer 1

Answer:

${a}^{3}+{b}^{3}-3ab+1=0$

Step-by-step explanation:

a+b+1=0

a+b= -1

Cubing on both sides

${(a+b)}^{3}={a}^{3}+{b}^{3}+3ab(a+b)\\{(a+b)}^{3}={a}^{3}+{b}^{3}-3ab\\-1={a}^{3}+{b}^{3}-3ab\\{a}^{3}+{b}^{3}-3ab+1=0$

Hope it Helps