Question

if a:b=1:2,b:c=3:2,d:c=5:6, then find a:b:c:d

Answer 1

Step-by-step explanation:

Well a:b= 1:2 and b:c= 3:2, multiplying both, we get

a:c= 3:4. Now d:c =5:6, inversing both sides, c:d= 6:5

thus now multiplying both equations,

a:d= 18:20 or a:d= 9:10. Now b:c=3:2 and c:d= 6:5, thus again multiplying,

b:d= 18:10 or 9:5.

Multiplying 18/18 a:b, we get a:b= 18:36

Similarly, a:c= 3:4×6/6= 18:24 and a:d= 18;20

Thus a = 18, b=36, c= 24, d= 20

thus a:b:c:d = 18:36:24:20= 3:6:4:20