Math, asked by anshuGoel, 10 months ago

If a:b=1:2,
b: c= 3:5,c:d= 5:4 and e: d = 5:6, the find the value
of a :b:c:d:e.
(A) 1:2:3:4:5
B) 9:18:30:24:20
(D) 3:6:10:8:7
(C) 1:6:4:5:6​

Answers

Answered by aditimukherjee1012
3

Step-by-step explanation:

You have to find a way to make each of the letters, besides the a and e the same in the shared ratios. Like in the 1st ratio, b is 1, but in the 2nd, b is 3. The LCM would be 6. that makes a:b = 3:6 and b:c=6:10. So now a:b:c=3:6:10. So, c in this ratio is 10, but c in the 3rd ratio is 5. LCM=10. Change the 3rd ratio to c:d=10:8.

So, now we have a:b:c:d=3:6:10:8 with d being 8. Flipping the 4th ratio, we get d:e=6:5, with d being 6. So, the LCM for d is 24. Multiplying the abcd by 3 to make d 24 gives us, a:b:c:d=9:18:30:24. The d:e ratio multiplied by 4 becomes 24:20.

Now we can make the final link. a:b:c:d:e=9:18:30:24:20

please tell me do you understand!!

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