Question

If a/b=1/3 and b/c=1/3 then find b/a+c

Answer 1

Answer:

a/b=1/3

3a=b

=a=b/3

b/c=1/3

3b=c

b/a+c

$\frac{b}{a + c}$

$\frac{b}{ \frac{b}{3} + 3b }$

$\frac{b}{ \frac{b + 9b}{3} }$

$\frac{3b}{b + 9b}$

$\frac{3b}{b(1 + 9)}$

$\frac{3}{10}$

Explanation:

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