If A:B=1:3,B:C=5:7and C:D=9:7,then what ratio is equal to A:B:C:D ?
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A:B=1:3
A/B=1/3 =1/3×15/15=15/45
B:C=5:7
B/C=5/7×9/9= 45/63
C:D=9:7
C/D=9/7×7/7=63/49
A:B:C:D=15:45:63:49
A:B=1:3
A/B=1/3 =1/3×15/15=15/45
B:C=5:7
B/C=5/7×9/9= 45/63
C:D=9:7
C/D=9/7×7/7=63/49
A:B:C:D=15:45:63:49
Anonymous:
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A : B = 1 : 3
B : C = 5 : 7
We need to make ratios in cases equal. So, B can have 15 but at the stage C can't have same ratio
LCM of 7 , 9 is 63
To obtain 63 ; B : C = 45 : 63 and C : D = 63:49
Now we have B as 45 ,so A : B = 15 : 45
Finally, A : B : C : D = 15 : 45 : 63 : 49
B : C = 5 : 7
We need to make ratios in cases equal. So, B can have 15 but at the stage C can't have same ratio
LCM of 7 , 9 is 63
To obtain 63 ; B : C = 45 : 63 and C : D = 63:49
Now we have B as 45 ,so A : B = 15 : 45
Finally, A : B : C : D = 15 : 45 : 63 : 49
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