Question

If a-b= 1, a²+b² = 13 find ab

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Answer 1

ANSWERGiven, a + b = 5 and a 2 +b 2 =13On squaring a + b = 5 both sides, we get(a+b) 2 =(5) 2 a 2 +b 2 +2ab=2513+2ab=25⇒2ab=25−13=12⇒ab=12/2=6∴ab=6

Answer 2

Wehave

a+b=5

bysquaringbothsides

(a+b)

2

=5

2

a

2

+b

2

+2ab=25

13+2ab=25

2ab=25−13

2ab=12

∴ ab = 6

Hence, the value of ab is 6.

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