If (a-b) = 1, & ab=6; find (a^3-b^3) (step by step)
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idk srry
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a^3-b^3= (a-b) ( a^2+ab+b^2)
from (a-b)^2 =a^2+b^2+2ab
( 1) ^2 = a^2+b^2+ 2 (6)
1 = a^2+b^2+ 12
a^2+b^2= -11
so, a^3-b^3= ( 1 ) ( -11+6)
a^3-b^3 = -5
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