If a + b = 1 and a – b = 7; find : (i) a² + b² (ii) ab
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Answered by
0
Answer:
a^2+b^2=(a+b)^2-2ab
=1^2-2ab
or
(a-b)+2ab=7^2-2ab= 49-2ab
Answered by
0
Step-by-step explanation:
I) a²-b²
we know
a²-b²=(a+b)(a-b)
1*7=7
So a²-b²=7
II) ab
(a+b)²=a²+b²+2ab
(1)²=7+2ab
1=7+2ab
2ab= -6
ab= -3
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