Math, asked by sisters3, 4 hours ago

if a+b=1 and a-b=7.Find the value of5(a^2+b^2).​

Answers

Answered by karishmarahi
2

Step-by-step explanation:

something error in question

plz check that

5(a^2-b^2) instead of 5(a^2+b^2)

5(a^2-b^2)

5[(a+b)(a-b)]

5(1×7)

5×7

35

hope it will help you

Answered by Abhishek802271
9

Answer:

a+b=1

a-b=7

5(a2-b2)

5(a+b)(a-b)

5*1*7=35

This is the correct answer.

Step-by-step explanation:

i hope this will help you.

thank u

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