if a+b=1 and a-b=7.Find the value of5(a^2+b^2).
Answers
Answered by
2
Step-by-step explanation:
something error in question
plz check that
5(a^2-b^2) instead of 5(a^2+b^2)
5(a^2-b^2)
5[(a+b)(a-b)]
5(1×7)
5×7
35
hope it will help you
Answered by
9
Answer:
a+b=1
a-b=7
5(a2-b2)
5(a+b)(a-b)
5*1*7=35
This is the correct answer.
Step-by-step explanation:
i hope this will help you.
thank u
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