Math, asked by harshshivhare63622, 8 months ago

if a+b=1 and ab=0 then find a3+b3​

Answers

Answered by ʙᴇᴀᴜᴛʏᴀɴɢᴇʟ
4

Step-by-step explanation:

Given a/b + b/a = 1

(a^2 + b^2)/ab = 1.

a^2 + b^2 = ab --- (1)

Then a^3 + b^3 = (a + b)(a^2 + b^2 - ab)

= (a + b)(ab - ab) (From (1))

=0

Answered by Mounikamaddula
4

Answer:

Given that,

a+b=1

ab=0

Cubing on both sides,

(a+b)³=1³

a³+b³+3ab(a+b)=1

a³+b³+3(0)(1)=1

a³+b³+0=1

a³+b³=1

So the value of,a³+b³ is 1.....

Step-by-step explanation:

Hope it helps you frnd.......

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