if a+b=1 and ab=0 then find a3+b3
Answers
Answered by
4
Step-by-step explanation:
Given a/b + b/a = 1
(a^2 + b^2)/ab = 1.
a^2 + b^2 = ab --- (1)
Then a^3 + b^3 = (a + b)(a^2 + b^2 - ab)
= (a + b)(ab - ab) (From (1))
=0
Answered by
4
Answer:
Given that,
a+b=1
ab=0
Cubing on both sides,
(a+b)³=1³
a³+b³+3ab(a+b)=1
a³+b³+3(0)(1)=1
a³+b³+0=1
a³+b³=1
So the value of,a³+b³ is 1.....
Step-by-step explanation:
Hope it helps you frnd.......
Similar questions