If a- b = 1 and ab =12, then a²+b² =
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Answered by
1
Answer:
GIVEN
a-b=1
squaring on both the sides
(a-b)²=a²+b²-2ab
so putting the given values we get
(1)²=a²+b²- 2×12
a²+b²=24+1
a²+b²=25
if you understand pls mark me brainliest
Answered by
1
a=4
b = 3
therefore a^2-b^3=( a-b)^2ab
=(4-3)^2 +2*4*3
=1+24
= 25
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