If a+b=1 find vale of a³+b³+3ab
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0
Answer:
a
2
−1)(b
2
−1)+4ab
=a
2
b
2
−a
2
−b
2
+1+2ab+2ab
=(ab)
2
+2(ab)(1)+1
2
−(a
2
−2ab+b
2
)
=(ab+1)
2
−(a−b)
2
=(ab+1+a−b)(ab+1−a+b)
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