If a+b=1, prove that a^3+b^3+3ab=1.
Answers
Answer- The above question is from the chapter 'Polynomials'.
Let's know about polynomials first.
Polynomial- It is an algebraic expression involving use of variables and constants.
p(x)- It is used to denote a polynomial. It is read is 'Polynomial in x'.
Polynomials can be classified on two basis:
1) Number of terms
E.g.- Polynomial with one term is called monomial.
Two terms- binomial
Three terms- trinomial
2) Power of variable
E.g.- Polynomial with degree 1 is called linear polynomial.
degree 2- quadratic polynomial
degree 3- cubic polynomial
degree 4- biquadratic polynomial
Concept used: (x + y)³ = x³ + y³ + 3xy(x + y)
Given question: If a + b = 1, prove that a³ +b³ + 3ab = 1.
Solution: a + b = 1 (Given)
Cubing both sides, we get,
(a + b)³ = 1³
a³ + b³ + 3ab(a + b) = 1 ∵ (x + y)³ = x³ + y³ + 3xy(x + y) where x = a and y = b
a³ + b³ + 3ab × 1 = 1 ∵ a + b = 1 (Given)
⇒ a³ + b³ + 3ab = 1
Hence, proved.