Math, asked by royk90614, 1 month ago

if a+b=1 , prove that a^3+b^3+3ab=1.​

Answers

Answered by amitsauyhu22556688
1

Answer:

We know that (a−b)

3

=a

3

−b

3

−3ab(a−b)

Given that

a−b=1

Cubing on both sides, we get

⇒(a−b)

3

=a

3

−b

3

−3ab(a−b)

Substituting the value of a−b we get,

⇒(1)

3

=a

3

−b

3

−3ab(1)

Therefore, ⇒a

3

−b

3

−3ab=1

Step-by-step explanation:

if a+b=1 , prove that a^3+b^3+3ab=1.

Answered by Anonymous
2

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