if a+b=1 , prove that a^3+b^3+3ab=1.
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Answered by
1
Answer:
We know that (a−b)
3
=a
3
−b
3
−3ab(a−b)
Given that
a−b=1
Cubing on both sides, we get
⇒(a−b)
3
=a
3
−b
3
−3ab(a−b)
Substituting the value of a−b we get,
⇒(1)
3
=a
3
−b
3
−3ab(1)
Therefore, ⇒a
3
−b
3
−3ab=1
Step-by-step explanation:
if a+b=1 , prove that a^3+b^3+3ab=1.
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