If a-b=1 prove that a^3+b^3=(a+b)(1+ab)
Anonymous:
I guess ur question is wrong!
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given ,
a-b=1
LHS=a^3+b^3
=(a+b)(a^2+b^2-ab) -----------(1)
now,
a-b=1
take square both side
a^2+b^2-2ab=1
add both side ab
a^2+b^2-ab=1+ab
put this equation (1)
now ,
LHS=(a+b)(1+ab)=RHS
a-b=1
LHS=a^3+b^3
=(a+b)(a^2+b^2-ab) -----------(1)
now,
a-b=1
take square both side
a^2+b^2-2ab=1
add both side ab
a^2+b^2-ab=1+ab
put this equation (1)
now ,
LHS=(a+b)(1+ab)=RHS
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0
HENCE PROVED ...............................
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