Question

if a+b =1 ,prove that a³+b³+3ab=1​

Answer 1

Answer:

a+b=1

a^3+b^3+3ab

=(a+b)^3-3ab(a+b)+3ab

=(1)^3-3ab.1+3ab

=1-3ab+3ab

=1 (proved)

Answer 2

(a+b)= 1

(a+b)^3 = 1^3

a^3 + b^3 + 3ab(a+b) = 1

a^3 + b^3 + 3ab = 1

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