If a-b=1 then I a3-b3-3ab
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Answer:
-1-3a+3a^2
Step-by-step explanation:
a-b=1 then
b=1+a
ATQ,
a^3-b^3-3ab
a^3-(1+a)^3-3[a*(1+a)]
a^3-(1+a^3)-3[a+a^2]
a^3-1-a^3-3a-3a^2
-1-3a+3a^2
I think this is the answer
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