If a+b=-1 then the value of a³+b³-3ab is
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Answer:
answer is 1
Step-by-step explanation:
(a+b)(a-b)=1
a²-ab+ab-b²=1
a²+b²=1
(a+b)²=a²+b²+2ab
(-1)²=(1)+2ab
1-1=2ab
ab=0
(a-b)²=a²+b²-2ab
(a-b)²= 1-2(0)
a-b=√1
a-b=1
(a-b)³ =a³+b³-3ab
(1)³ =a³+b³-3(0)
a³+b³=1
value of a³+b³-3ab
1-3(0)
=1
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