Question

If a+b=10,a²+b²=58, find a³+b³

Answer 1

Answer:

370

Step-by-step explanation:

a+b=10.....................(1)

a²+b²=58

(a+b)²=a²+b²+2ab

100=58+2ab

42=2ab

ab=21

(a-b)²=a²+b²-2ab

(a-b)²=58-42

(a-b)²=16

a-b = 4.............(2)

(1)+(2)

2a=14

a=7

Sub in (2)

7-b=4

b=3

a³+b³=7³+3³= 343+27 = 370

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