if a+b=10,ab=21.then a cube+b cube=
Answers
Answered by
6
a+b= 10
ab= 21
a3+b3= (a+b) (a2+b2-ab)
(a+b)2= a2+b2+2ab
10^2= a2+b2+2x21
100= a2+b2+42
100-42= a2+b2
a2+b2= 58
a3+b3= 10x 58-(21)
a3+b3= 10x 37
a3+b3= 370
ab= 21
a3+b3= (a+b) (a2+b2-ab)
(a+b)2= a2+b2+2ab
10^2= a2+b2+2x21
100= a2+b2+42
100-42= a2+b2
a2+b2= 58
a3+b3= 10x 58-(21)
a3+b3= 10x 37
a3+b3= 370
Answered by
3
a+b = 10 and ab = 21
a³+b³ = (a+b)³ - 3a²b-3ab²
→ (10)³ - 3ab(a+b)
→ 10³ - 3(21)(10)
→ 1000-630
→ 370
Hope it helps
a³+b³ = (a+b)³ - 3a²b-3ab²
→ (10)³ - 3ab(a+b)
→ 10³ - 3(21)(10)
→ 1000-630
→ 370
Hope it helps
Similar questions