if a+b=10,ab=3 find a³+b³
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Answered by
2
EXPLANATION.
=> a + b = 10
=> ab = 3
To find the value of a³ + b³.
=> a + b = 10 .......(1)
=> ab = 3 ........(2)
From equation (2) we get,
=> ab = 3
=> a = b/3 .......(3)
put the value of equation (3) in equation (1)
we get,
=> b/3 + b = 10
=> b + 3b = 30
=> 4b = 30
=> b = 30/4
=> b = 15/2
Put the value of b = 15/2 in equation (3)
we get,
=> a = b/3
=> a = 15/2/3
=> a = 15/2 X 1/3
=> a = 5/2
Formula of => a³ + b³
=> ( a + b ) ( a² - ab + b² )
=> ( 5/2 + 15/2 ) [ ( 5/2)² - ( 5/2 X 15/2 ) + ( 15/2)²
=> 10 [ 25/4 - 75/4 + 225/4 ]
=> 10 [ 250 - 75 / 4 ]
=> 10 [ 175/4 ]
=> 5 X 175 / 2
=> 875/2
Therefore,
value of a³ + b³ = 875/2.
Answered by
1
Step-by-step explanation:
( a + b ) ³ = 10³
a³+b³+3ab(a+b)= 1000
a³+b³+3*3(10)= 1000
a³+b³+9*10= 1000
a³+b³+90= 1000
a³+b³= 1000 - 90
a³+b³= 910
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