Question

If a+b=10 and a^2+b^2=58 than the value of a^3+b^3​

Answer 1

hey ..!!

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given here

a+b=10. ...(1)

a²+b²=58. (2)

find here

a³+b³=?

Solution "--

we know that

(a+b)²=a²+b²+2ab

so,

put value by (1) and (2)

we get,

(10)²=58+2ab

=>100=58+2ab

=>2ab=100-58

=>2ab=42

=>ab=42/2

=>ab=21

now,

(a+b)³=a³+b³+3ab(a+b)

put value by (1)and (2)

(10)³=a³+b³+3×21(10)

=>1000=a³+b³+63(10)

=>1000=a³+b³+630

=>a³+b³=1000-630

=>a³+b³=370

I hopes its helps u

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Answer 2

Answer:

370

Step-by-step explanation:

370