Question

if a + b = 10 and a^2+b^2=58 then find the a^3+b^3​

Answer 1

Answer:

=(a^3+b^3)

=(a+b)×(a^2+b^2)

=10 × 58

=580

Step-by-step explanation:

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Answer 2

$here \: is \: u \: r \: answer \\ \\ step \: by \: step \: explanation \\ \\ \\ \\ given \: \: \: \: a + b = 10 \: \: \: \: {a}^{2} + {b}^{2} = 58 \\ \\ to \: find \: {a}^{3} + {b}^{3} \\ \\ {a}^{3} + {b}^{3} = (a + b)( {a}^{2} - ab + {b}^{2} ) \: \: \: {equation \: 1} \\ \\ substitute \: given \: in \: eq \: 1 \\ \\ {a}^{3} + {b}^{3} = (10)(58 - ab)$

alternative method:

a^3+b^3=(a+b)(a^2+b^2)

=10(58)

=580

mark as brainliest