If a + b = 10 and a2 + 12 = 58, find the value of a3 + b3.
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Answered by
1
Answer:
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Step-by-step explanation:
a + b = 10
SOBS
a² + b² + 2ab = 100
58 + 2ab = 100
2ab = 42
ab = 21
a³ + b³ = (a + b)(a² + b² - ab)
a³ + b³ = 10 × (58 - 21)
a³ + b³ = 370
Answered by
1
Step-by-step explanation:
a + b = 10
+ b2 = 58
a3+ b3 = ?
(a+b)^2 = a^2+b^2+2ab
( 10 )^2 = 58+2ab
100-58 = 2ab
42 = 2ab
ab = 21
(a+b)^3 = a^3+b^3+3ab(a+b)
a^3+b^3 = (a+b)^3 - 3ab(a+b)
a^3+b^3 = (10)^3 - 3×21× 10
a^3+b^3 = 1000 - 630
a^3+b^3 = 370
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