Question

if a+b = 10 and a²+b²=58 find a³+b³​

Answer 1

Answer:

370

Step-by-step explanation:

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Answer 2

Answer:

370

Step-by-step explanation:

Given, a+b=10

a²+b²=58=>(a+b)²-2ab=58

=>10²-2ab=58

=>2ab=100-58

=>2ab=42

=>ab=21

Therefore, ab=21-------------------------(I)

Since,We know that x³+y³=(x+y)(x²+y²-xy)

Therefore, a³+b³=(a+b)(a²+b²-ab)

=(10)(58-21) [From (I)]

=(10)(37)

=370

Hence, a³+b³=370

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