Question

If a+b=10 and a²+b²=58 find the value of a³+b³​

Answer 1

Answer:

a²+b²= 58. We know that (a+b)²=a² +b²+2ab (10)²=58+2ab 100=58+2ab 100-58= 2ab 42= 2ab 21= ab. Now , (a+b)³=a³+b³+3ab(a+b)

Step-by-step explanation:

may it will help you out

Answer 2

Step-by-step explanation:

a²+b²=(a+b)²-2ab

58=100-2ab

42=2ab

ab=21

Now,

a³+b³

=(a+b)(a²+b²-ab)

=10(58-21)

=10.37

=370