Math, asked by ayush33475627, 1 year ago

If a+b=10 and a2 + b2=58 then the value of a3+b3 is​

Answers

Answered by Anonymous
6

Answer:

Step-by-step explanation:

a+b=10

cubing both the sides

(A+b)3= A3+b3+3ab(a+b)=1000

A2+b2=58

(a+b)=10

sqauring both the sides

A2+b2+2ab=100

58+2ab=100

2ab=42

ab=21

(A+b)3= A3+b3+3ab(a+b)

A3+b3+3(21)(10)=1000

A3+b3=1000-630

A3+b3=370

answer is 370

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