if a+b=10 and ab=16 then find a²+b²
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Answered by
33
Hi,
a + b = 10 -------( 1 )
ab = 16 ----------( 2 )
Square the equation ( 1 ),
( a + b )^2 = ( 10 )^2
a^2 + b^2 + 2ab = 100
a^2 + b^2 + 2 × 16 = 100 [ from ( 2 ) ]
a^2 + b^2 + 32 = 100
a^2 + b^2 = 100 - 32
a^2 + b^2 = 68
I hope this helps you.
:)
a + b = 10 -------( 1 )
ab = 16 ----------( 2 )
Square the equation ( 1 ),
( a + b )^2 = ( 10 )^2
a^2 + b^2 + 2ab = 100
a^2 + b^2 + 2 × 16 = 100 [ from ( 2 ) ]
a^2 + b^2 + 32 = 100
a^2 + b^2 = 100 - 32
a^2 + b^2 = 68
I hope this helps you.
:)
Answered by
20
Hi !
a + b = 10 -------( 1 )
ab = 16 ----------( 2 )
Squaring equ.1 , we get :-
( a + b )² = 10²
a² + 2ab + b² = 100
a² + 2 × 16 + b² = 100
a² + b² + 32 = 100
a²+ b² = 100 - 32
a² + b² = 68
a + b = 10 -------( 1 )
ab = 16 ----------( 2 )
Squaring equ.1 , we get :-
( a + b )² = 10²
a² + 2ab + b² = 100
a² + 2 × 16 + b² = 100
a² + b² + 32 = 100
a²+ b² = 100 - 32
a² + b² = 68
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