Question

If a + b=10 and ab=2, then find the value of: (a - b)∆2

Answer 1

Given:

a+b=10 ab=2

To find: (a-b)^2

as, (a+b)^2 = a^2 + b^2 + 2ab

(10)^2 = a^2 + b^2 + 2(2)

100 - 4 = a^2 + b^2

96 = a^2 + b^2 ( eq.1 )

as,

(a-b)^2 = a^2 + b^2 - 2ab

equating a^2 + b^2 value from EQ.1

(a-b)^2 = 96-4

a-b = √92

Answer 2

Answer:

ummmm

Step-by-step explanation:

maths?

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