Question

If a + b = 10 and ab = 2, then find the value of : (i) a2 + b2 (iiy (a - b)2
(Hint: (1) Given a + b = 10, we have. On squaring both sides, a+ b2 + 2ab = 100
Given ab = 2, we get a2 + b2 = 96)​

Answer 1

$solution \\ \\ a + b = 10 \: .......(1) \\ \\ ab = 2 \: ....(2) \\ \\ from \: eq \: no.2 \: we \: \: get \: \\ \\ a = \frac{2}{b} \\ \\ now \: substitute \: a \: value \: in \: eq \: 1 \: we \: get \: \\ \\ \frac{2}{b} + b = 10$

Answer 2

Answer:

${a}^{2} + {b}^{2} = 96$

$(a - b) ^{2} = 92$

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