Question

If a + b = 10 and ab = 21, find the value of a3 + b3
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Answer 1

Answer:

(a+b)(a²+b²-ab)

10{(a+b)²+2ab-ab}

10*(100+42-21)

10*(100+21)

10*121

1210

hopefully this will help

Answer 2

Answer:

the answer is 370

Step-by-step explanation:

Given :-a+b = 10

ab = 21a³+b³

= (a+b)³ - 3ab [ a+ b ]

= (10)³ - 3ab(a+b )

= 1000 - 3 × 21 × 10

= 1000 -630

= 370.

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