If a+b = 10 anf a.b= 21 then a square + b square =?
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(a+b)^2 =a^2+b^2+2ab
Now substituting values
10^2=a^2+b^2+2×21
100-42= a^2+b^2
hence
a^2+b^2= 58
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Now substituting values
10^2=a^2+b^2+2×21
100-42= a^2+b^2
hence
a^2+b^2= 58
here's ur answer please mark it brainlliest buddy plplzplzpzl here's ur answer please mark it brainlliest buddy plplzplzpzl here's ur answer please mark it brainlliest buddy plplzplzpzl here's ur answer please mark it brainlliest buddy plplzplzpzl
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