If a+b = 10 anf a.b= 21 then a square + b square =?
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(a+b)^2 =a^2+b^2+2ab
Now substituting values
10^2=a^2+b^2+2×21
100-42= a^2+b^2
hence
a^2+b^2= 58
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Now substituting values
10^2=a^2+b^2+2×21
100-42= a^2+b^2
hence
a^2+b^2= 58
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