Question

If a+ b = 100
a-b= 50

Then prove that 53(a) × ( 47) b -100 (ab)< 7788376

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

Given, a + b = 100     ...( i )

           a - b = 50      ...( ii )

Adding ( i ) and ( ii ) : -

a + b = 100

a - b = 50

2a    = 150

= >  a = 150 / 2

= > a = 75

Substituting the value of a in ( i ) : -

= > a + b = 100

= > 75 + b = 100

= > b = 100 - 75

= > b = 25

Therefore,

= > 53( a ) x 47( b ) - 100( ab )

= > 53( 75 ) x 47( 25 ) - 100( 75 x 25 )

= > 3975 x 1175 - 187500

= > 4670625 - 187500

= > 4,483,125

Which is less than 7788376.

Hence, proved that 53(a) × ( 47) b -100 (ab)< 7788376.

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