If a+b=10and ab=21find the value of a³+b³
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a+b=10
ab=21
a^3+b^3=?
a^3+b^3
=(a+b)(a^2+b^2-ab)
since (a+b)^2=a^2+b^2+2ab
so when we subtract above equation by ab then it will a^2+b^2-ab
=10{(a+b)^2-3ab}
=10{10^2-3(21)}
=10(100-63)
=10×37
=370
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