Question

if a+b=11,a²+b²=73 Then find a²-b² by using identities
Plz solve it fast​

Answer 1

Answer:

55

Step-by-step explanation:

a plus b ka whole square is equal to 121 2ab equal to 48. a-b ka whole square equal to a square + b square - 2 a b. a square + b square ka man rakhne per a minus b is equal to 5 thus (a-b)×(a+b) equal to 5×11 equal to 55

Answer 2

$\mathtt{ a+b = 11}$

$\texttt{Squaring both sides,}$

$\mathtt{(a+b)² = 11²}$

$\mathtt{a²+b²+2ab = 121}$

$\mathtt{73+2ab = 121} \;\;\;\;\; \mathtt{[a²+b²=73]}$

$\mathtt{2ab = 121-73}$

$\mathtt{2ab = 48}$

$\mathtt{ab = \large\frac{48}{2}}$

$\mathtt{ab = 2}$

$\texttt{Now,}$

$\mathtt{(a-b)² = (a+b)²-4ab}$

$\mathtt{(a-b)² = 121 - 4×24}$

$\mathtt{(a-b)² = 121-96}$

$\mathtt{(a-b)² = 25}$

$\mathtt{(a-b) = \sqrt{25}}$

$\mathtt{(a-b) = 5}$

$\texttt{ We know that,}$

$\mathtt{a²-b² = (a+b)(a-b)}$

$\mathtt{a²-b² = 11×5}$

$\mathtt{a²-b² = 55}$