If a+b=11 ab=28 find value of a³+b³
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a³+b³= (a+b)(a²-ab+b²)
=> (a+b)[(a+b)²-2ab-ab]
==> (11)[(11)²-3×28]
==> (11)[121-84]
==> (11)[37]
==> 407
=> (a+b)[(a+b)²-2ab-ab]
==> (11)[(11)²-3×28]
==> (11)[121-84]
==> (11)[37]
==> 407
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