Question

if a+b=11 and a^2+b^2=65, find the value of ab​

Answer 1

Answer:

28

Step-by-step explanation:

Given a+b=11

a^2+b^2=65

we know that (a+b)^2=a^2+b^2+2ab

(11)^2=65+2ab

121=65+2ab

121-65=2ab

56=2ab

56/2=ab

28=ab