if a+b=12,a-b=2√3, find the value of ab is
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Answer:
Subtracting both equations.
a + b = 12
(-)a - b = 2root3
2b = 12-2root3
b = 12-2root3/2 = 6-root3
To find a put value of b in
a + b = 12
a + (12-2root3/2) = 12
a = 12-(12-2root3/2)
a = 12-12+2root3/2
a = 24-12+2root3/2
a = 12+2root3/2
a = 6+root3
Now, a × b = (6+root3)(6-root3)
By,(a+b)(a-b)=a²-b²
= 6²-(root3)²
= 36-3 = 33
Step-by-step explanation:
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