Math, asked by Somilguha7126, 5 hours ago

if a+b=12,a-b=2√3, find the value of ab is

Answers

Answered by kimrose1512
2

Answer:

Subtracting both equations.

a + b = 12

(-)a - b = 2root3

2b = 12-2root3

b = 12-2root3/2 = 6-root3

To find a put value of b in

a + b = 12

a + (12-2root3/2) = 12

a = 12-(12-2root3/2)

a = 12-12+2root3/2

a = 24-12+2root3/2

a = 12+2root3/2

a = 6+root3

Now, a × b = (6+root3)(6-root3)

By,(a+b)(a-b)=a²-b²

= 6²-(root3)²

= 36-3 = 33

Step-by-step explanation:

hi

hope it helps you...

Similar questions