if a +b=12, a²+b²=90.find a³+b³
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Answer:
(a+b)=12
(a+b)²=a²+b²+2ab
substitute the values
(12)²=90+2ab
24=90+2ab
24-90=2ab
-66/2=ab
-33=ab.......(1)
a²+b²=90
a²+b²-2ab=90-2ab
(a-b)²=90-(-66).... from (1)
(a-b)²=90+66
(a-b)²=156
a-b=12.4
a³+b³=(a-b)(a²+ab+b²)........ formula
a³+b³=12.48(90-33)
=12.48(57)
=711.36
~711
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