If a+b = 12 , ab= 32 find the values of a^2 + b^2 and ( a + b )^2
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a=4
b=8
hope this helps
b=8
hope this helps
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Answered by
3
a^2+b^2
=(a+b)^2-2ab
given,
a+b=12 ,ab=32
putting the value
=(12)^2-2*32
=144-64
=80 ans
(a+b)^2
=a^2+b^2+2*ab (a^2+b^2=80)
=80+2*32
=80+64
=144 ans
may it helped you
=(a+b)^2-2ab
given,
a+b=12 ,ab=32
putting the value
=(12)^2-2*32
=144-64
=80 ans
(a+b)^2
=a^2+b^2+2*ab (a^2+b^2=80)
=80+2*32
=80+64
=144 ans
may it helped you
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