if a+b =12 and ab=27,find the value of a³+b³
Answers
Answered by
179
Hey !!!
a + b = 12 |given|
ab = 27
•°• we know that
a³ + b ³ = (a + b ) ( a² + b² - ab )
and , ( a + b ) ²- 2ab = a² + b²
so , a³ + b³= ( a + b ){ ( a + b )² - 3ab }
hence , a³ + b³ = 12{12²- 3 ×27 } ✔ putting the given value
=> 12 { 144- 3×27 }
=> 12×63
= > 756 Answer
a³ + b³ = 756 Answer
___________________
Hope it helps you !!
#Rajukumar111
a + b = 12 |given|
ab = 27
•°• we know that
a³ + b ³ = (a + b ) ( a² + b² - ab )
and , ( a + b ) ²- 2ab = a² + b²
so , a³ + b³= ( a + b ){ ( a + b )² - 3ab }
hence , a³ + b³ = 12{12²- 3 ×27 } ✔ putting the given value
=> 12 { 144- 3×27 }
=> 12×63
= > 756 Answer
a³ + b³ = 756 Answer
___________________
Hope it helps you !!
#Rajukumar111
janidhruw:
give me correct answer
Answered by
122
Answer :
Now,
a³ + b³
= (a + b)³ - 3ab(a + b)
= 12³ - (3 × 27 × 12) [∵ a + b = 12, ab = 27]
= 1728 - 972
= 756
#MarkAsBrainliest
Now,
a³ + b³
= (a + b)³ - 3ab(a + b)
= 12³ - (3 × 27 × 12) [∵ a + b = 12, ab = 27]
= 1728 - 972
= 756
#MarkAsBrainliest
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