if a-b=12and ab=14 then find the value of a^2+b^2+ab.plz solve it fast
Answers
Answered by
4
★ Ello ★
here is your answer !!
( a - b ) ² = a² + b² - 2 × a × b
=> ( 12 )² = a² + b² - 2 × 14
144 + 28 = a² + b²
=> 172
now , ab = 14
now ,
a² + b² + ab => 172 + 14
=> 186
hope it helps you dear !!
here is your answer !!
( a - b ) ² = a² + b² - 2 × a × b
=> ( 12 )² = a² + b² - 2 × 14
144 + 28 = a² + b²
=> 172
now , ab = 14
now ,
a² + b² + ab => 172 + 14
=> 186
hope it helps you dear !!
kashish190:
my answer is correct hahaha
Answered by
9
HELLO DEAR,
GIVEN THAT:-
a - b = 12 ---------( 1 ),
ab = 14
Now,
From-----( 1 )
(a - b)² = 12²
a² + b² - 2ab = 144
[a² + b² - 2(14)] = 144
(a² + b²) = 144 + 28
(a² + b²) = 172
∴ [ adding "(ab)" both side]
(a² + b² + ab) = 172 + ab
(a² + b² + ab) = 172 + 14
(a² + b² + ab) = 186
I HOPE ITS HELP YOU DEAR,
THANKS
GIVEN THAT:-
a - b = 12 ---------( 1 ),
ab = 14
Now,
From-----( 1 )
(a - b)² = 12²
a² + b² - 2ab = 144
[a² + b² - 2(14)] = 144
(a² + b²) = 144 + 28
(a² + b²) = 172
∴ [ adding "(ab)" both side]
(a² + b² + ab) = 172 + ab
(a² + b² + ab) = 172 + 14
(a² + b² + ab) = 186
I HOPE ITS HELP YOU DEAR,
THANKS
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