Question

if a+b=13 a+d=8 d+C=8 and b-c=6 then find the value of a, b, C, d as an integer
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Answer 1

Step-by-step explanation:

Can it be solved: a+b=8;c−d=6;a+c=13;b+d=8 ?

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Given in the question that

1)a+b=8

2)c-d=6

3)a+c=13

4)b+d=8

From 1) b=8-a

Substitute ‘b’ value in 4)

Then 4) becomes

(8-a)+d=8

d-a=8–8=0

d=a

Replace 'd' with 'a' in 2)

2) c-a=6

3) a+c=13

Summing up 2) & 3) will give value of ‘c,a&d’

2c=19, c=9.5

Substitute c value in 2)

a= 9.5–6

a=d=3.5

Substituting ‘a=d=3.5’ value in 1) or 4), gives value of 'b'

b=4.5

a=3.5, b=4.5, c=9.5, d=3.5

Solved!

Answer 2

Answer:

Step-by-step explanation:

a+b = 13

a+d= 8

and d+c = 8

b-c=6

to find : value of a,b,c

a = 4

b= 10

and c= 4