Math, asked by santoshsaha, 5 months ago

If a+b=13, ab = 40 and a>b then find the value of a^2-b^2?

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Answers

Answered by anveshsingh444
2

Answer:

39

Step-by-step explanation:

(a+b)²=13²

a²+b²+2ab=169

putting value of ab=40

a²+b²=89

subtracting 2ab from both the sides

(a-b)²=9

therefore. taking square root both sides

a-b=3

(a+b) ×(a-b) =13× 3=39

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