If a+b=13, ab = 40 and a>b then find the value of a^2-b^2?
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Answer:
39
Step-by-step explanation:
(a+b)²=13²
a²+b²+2ab=169
putting value of ab=40
a²+b²=89
subtracting 2ab from both the sides
(a-b)²=9
therefore. taking square root both sides
a-b=3
(a+b) ×(a-b) =13× 3=39
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