Question

if a + b =15 and a²+b²=60 then what is the value of a-b

Answer 1

Answer:

$a + b =15\\\\a^{2} +b^{2} =60\\(a+b)^2=a^{2} +b^{2} +2ab\\15^2=60+2ab\\2ab=165\\(a-b)^2=a^{2} +b^{2} -2ab\\\\(a-b)^2=60-165\\\\(a-b)^2=-105\\a-b=\sqrt{-105}$

Answer 2

Answer:

a-b=4

Step-by-step explanation:

a+b=15(1)

a²-b²

a-b=?

using identity

(A+B)(A-B)=a²-b²(2)

substituting the value of (1 and 2)

15*(a-b)=60

(a-b)=60/15

(a-b)=4

Mark as brainliest