if a + b =15 and ab =50.find the value of a^2 + b^2
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Step-by-step explanation:
given: a+b= 15.................(1)
ab= 50...................(2)
need to solve: a^2+b^2
equation (1) ; by squaring on both sides....
so, (a+b)^2= (15)^2
we know that: (a+b)^2= a^2+b^2+2ab
so, a^2+b^2+2ab= 225.................(3)
equation (4) multiply both sides by 4
so, 4(ab=50)
4ab= 200...............(4)
so by subtracting equations (3)-(4)
a^2+b^2+2ab-4ab= 225-200
so, a^2+b^2-2ab= 25
a^2+b^2-2ab= (a-b)^2
so, (a-b)^2= 25
a-b= √25=5
so, a-b= 5..................(5)
adding equations (1)+(5)
a+b+a-b= 15+5
by cancelling b..........
a+a= 20
2a=20
a=20/2=10
so, a=10
by , substituting in equation (1)
10+b=15
so, b=5
a=10, b=5
so, a^2+b^2= (10)^2+(5)^2= 100+25= 125
so, a^2+b^2= 125
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